如何在 processStartInfo 中传递多个参数? [英] How to pass multiple arguments in processStartInfo?

问题描述

我想从 c# 代码运行一些 cmd 命令.我关注了一些博客和教程并得到了答案，但我有点困惑，即我应该如何传递多个参数?

I want to run some cmd command from c#code. I followed some blogs and tutorial and got the answer, but I am in little bit confused i.e how should I pass multiple arguments?

我使用以下代码:

System.Diagnostics.Process process = new System.Diagnostics.Process();
System.Diagnostics.ProcessStartInfo startInfo = new System.Diagnostics.ProcessStartInfo();
startInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Normal;
startInfo.FileName = "cmd.exe";
startInfo.Arguments = 
...

以下命令行代码的 startInfo.Arguments 值是什么?

What will be the startInfo.Arguments value for the following command line code?

• makecert -sk server -sky exchange -pe -n CN=localhost -ir LocalMachine -is Root -ic MyCA.cer -sr LocalMachine -ss MyAdHocTestCert.cer

netsh http add sslcert ipport=127.0.0.1:8085 certhash=0000000000003ed9cd0c315bbb6dc1c08da5e6 appid={00112233-4455-696977-4455-696977-80000000000003ed9cd0c315bbb6dc1c08da5e6 appid={00112233-4455-696977-4455-896977-80000000000003>

推荐答案

纯粹是一个字符串:

startInfo.Arguments = "-sk server -sky exchange -pe -n CN=localhost -ir LocalMachine -is Root -ic MyCA.cer -sr LocalMachine -ss My MyAdHocTestCert.cer"

当然，当参数包含空格时，您必须使用 " " 将它们转义，例如:

Of course, when arguments contain whitespaces you'll have to escape them using " ", like:

"... -ss "My MyAdHocTestCert.cer""

请参阅 MSDN 为此.

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