如何在我存储的两个变量之间生成一个随机数? [英] How do I generate a random number between two variables that I have stored?

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问题描述


可能重复:

从某个范围生成随机整数

我是尝试创建一个程序,让计算机猜测用户脑海中的数字。唯一需要的用户输入是猜测是太高,太低还是正确。我在根据先前的猜测存储两个变量的最小值和最大值之间生成随机数时遇到问题。这是我的代码:

I am trying to create a program where the computer guesses a number the user has in his/her mind. The only user input required is whether the guess was too high, too low, or correct. I'm having a problem generating a random number between two variables that store the min and max based on previous guesses. Here is my code:

    #include <iostream>
    #include <cstdlib>
    #include <ctime>

    using namespace std;

    int main()
    {
        srand(static_cast <unsigned int> (time(0)));

        int compGuess = rand() % 100 +1; //Generates number between 1 - 100
        int highestNumber = 100;
        int lowestNumber = 1;
        char ready;
        char highLowSuccess;
        bool success;
        int tries = 0;


        cout << "Please pick a number between 1 - 100. I will guess your number. Don't tell me what it is!\n\n";


        do
        {
            cout << "Are you ready? (y/n)\n\n";
            cin >> ready;

            if (ready == 'y')
            {
                do
                {
                    cout << "Is your number " << compGuess << "?\n\n";
                    cout << "High, Low or Success?";
                    ++tries;
                    cin >> highLowSuccess; //User input telling the computer whether its too high, too low, or a success

                    if (highLowSuccess == 'h') //Executes code if number guessed was too high.
                    {

                        highestNumber = compGuess - 1; //Stores variable indicating the highest possible number based on user input
                        compGuess = rand() % highestNumber +1; //Generates a new random number between 1 and the new highest possible number
                        success = false;
                    }

                    else if (highLowSuccess == 'l') //Executes code if number guessed was too low.
                    {
                        lowestNumber = compGuess + 1;//Stores variable indicating the lowest possible number based on user input
                        compGuess = (rand() % highestNumber - lowestNumber + 1) + lowestNumber // <---- Not producing the desired result
                        success = false;
                    }

                    else if (highLowSuccess == 's') //Executes code if the computer's guess was correct.
                    {
                        cout << "I guessed your number! It only took me " << tries << " tries!";
                        success = true;
                    }


                } while (success != true);
            }


            else
            {
             continue;
            }

       } while (ready != 'y');



    return 0;

    }

最高数字是最大值,最低数字是分钟应该是。我需要一个方程式,使我可以生成一个随机数,同时考虑到最高和最低数。

highestNumber is what the max should be and lowestNumber is what the min should be. I need an equation that lets me generate a random number while taking the highest and lowest possible numbers into account.

请原谅我,如果答案真的很简单,我就是新手程序员。 xD

Forgive me if the answer is really simple, I'm a noob programmer. xD

推荐答案

要生成介于最小值和最大值之间的随机数,请使用:

To generate a random number between min and max, use:

int randNum = rand()%(max-min + 1) + min;

(包括最大值和最小值)

(Includes max and min)

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