如何将程序执行跳转到C中的特定地址？ [英] How to jump the program execution to a specific address in C?

问题描述

我希望程序跳到内存中的特定地址并从该地址继续执行。我曾考虑过使用 goto ，但是我没有标签，而只是内存中的地址。

I want the program to jump to a specific address in memory and continue execution from that address. I thought about using goto but I don't have a label rather just an address in memory.

无需担心从跳转地址返回。

There is no need to worry about return back from the jump address.

编辑：使用GCC编译器

edit: using GCC compiler

推荐答案

内联汇编可能是最简单，最优雅的解决方案，尽管这样做非常不寻常，除非您正在编写调试器

Inline assembly might be the easiest and most "elegant" solution, although doing this is highly unusual, unless you are writing a debugger or some specialized introspective system.

另一个选择可能是声明一个指向void函数的指针（ void（* foo）（void）），然后将指针设置为包含您的地址，然后调用它：

Another option might be to declare a pointer to a void function (void (*foo)(void)), then set the pointer to contain your address, and then invoke it:

void (*foo)(void) = (void (*)())0x12345678;
foo();

由于编译器认为您正在执行子例程调用，因此将某些东西压入堆栈您不在乎返回，这可能有用。

There will be things pushed on the stack since the compiler thinks you are doing a subroutine call, but since you don't care about returning, this might work.

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