获得chrono :: duration的无符号整数毫秒 [英] Get an unsigned int milliseconds out of chrono::duration
问题描述
对于Winapi包装器,我想在给定调用持续时间内使用chrono。代码示例:
For a winapi wrapper I want to use chrono for a duration given to the call. The code example:
bool setTimer(std::chrono::duration<std::chrono::milliseconds> duration)
{
unsigned int dwDuration = Do some chrono magic here
SetTimer(m_hWnd,1,dwDuration,0);
}
dw持续时间必须以毫秒为单位。
dwDuration has to be in milliseconds.
第一个问题:如何做魔术。
First question: How do to the magic.
第二个问题:参数声明可以吗?
Second question: Is the parameter declaration okay?
推荐答案
类型名称为 std :: chrono :: milliseconds
,它的成员函数为 count()
返回毫秒数:
The name of the type is std::chrono::milliseconds
, and it has a member function count()
that returns the number of those milliseconds:
bool setTimer(std::chrono::milliseconds duration)
{
unsigned int dwDuration = duration.count();
return std::cout << "dwDuration = " << dwDuration << '\n';
}
在线演示:http://coliru.stacked-crooked.com/a/03f29d41e9bd260c
如果您想成为超级- pedantic,count()的返回类型为 std :: chrono :: milliseconds :: rep
If you want to be ultra-pedantic, the return type of count() is std::chrono::milliseconds::rep
要处理小数毫秒,则类型将为 std :: chrono :: duration< double,std :: milli>
(count()的返回类型为然后加倍)
If you want to deal with fractional milliseconds, then the type would be std::chrono::duration<double, std::milli>
(and the return type of count() is then double)
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