是否可以使用模板类的单个参数将类型和该类型的指针传递给c ++模板类? [英] Is it possible to pass a type and a pointer of that type to a c++ template class using a single parameter of a template class?
问题描述
是否可以使用模板类的单个参数将类型和该类型的指针传递给c ++模板类?
Is it possible to pass a type and a pointer of that type to a c++ template class using a single parameter of a template class?
我想使用一个指向类型为 UART_HandleTypeDef
的嵌入式硬件地址(一个uart)的指针,并推断出该类型信息,而不是手动声明它。类似于以下内容:
I want to take a pointer to a embedded hardware address (an uart) which has the type UART_HandleTypeDef
and deduce that type information instead of manually declaring it. Something akin to:
template<typename T> class serial{
public:
T::value_type* uart = T;
};
我想摆脱通常的表示法,这需要我声明类型,然后传递一个指针:
I want to get away from the normal notation which would require me to state the type and then pass a pointer:
template<typename T,T* ptr> class c{
public:
T* _ptr = ptr;
};
更新:
我忘了:编译器支持C ++ 11之前的版本。它支持 一些 C ++ 11功能
update: I forgot to mention: pre C++11 is supported by my compiler. It supports some C++11 features
推荐答案
自C ++ 17起,您可能拥有
Since C++17, you might have
template <auto* ptr> class c
{
public:
auto _ptr = ptr;
};
在此之前,
template <typename T, T* ptr> class c
{
public:
T* _ptr = ptr;
};
是必经之路。
自C ++ 11起,MACRO就可以提供帮助
MACRO can help since C++11
#define TEMPLATE_AUTO(...) decltype(__VA_ARGS__), __VA_ARGS__
c<TEMPLATE_AUTO(my_ptr)> v;
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