如何保留隐式声明的聚合初始化构造函数？ [英] How to keep the implicitly declared aggregate initialization constructor?

问题描述

假设我有一个这样的类：

  struct X {
 char buf [10]; 
}; 
 X x { abc}; 
  

此编译。但是，如果我将用户定义的构造函数添加到该类，则将删除此隐式声明的聚合初始化构造函数：

  struct X {
 char buf [10]; 
 X（int，int）{} 
}; 
 X x { abc}; //编译错误
  

我如何声明我想要默认的聚合初始化构造函数，就像默认的那样构造函数 X（）= default ？谢谢。

解决方案

没有默认的聚合初始化构造函数。

聚合初始化仅在聚合上发生。除其他外，聚合是没有（用户提供的）构造函数的类型。

做您想做的正确方法是使工厂函数以您特殊的方式构造您的类型。

这样，类型可以保持聚合，但是有一种简便的方式可以按照您想要的方式对其进行初始化。

在需要时给类型构造函数强制用户调用构造函数来构造它。否则，您只需使用工厂功能。

Suppose I have a class like this:

struct X {
  char buf[10];
};
X x{"abc"};

This compiles. However, if I add user defined constructors to the class, this implicitly declared aggregate initialization constructor will be deleted:

struct X {
  char buf[10];
  X(int, int) {}
};
X x{"abc"}; // compile error

How can I declare that I want default aggregate initialization constructor, just like that for default constructor X()=default? Thanks.

解决方案

There is no "default aggregate initialization constructor".

Aggregate initialization only happens on aggregates. And aggregates are types that, among other things, don't have (user-provided) constructors. What you're asking for is logically impossible.

The correct means of doing what you want is to make a factory function to construct your type in your special way. That way, the type can remain an aggregate, but there's a short-hand way for initializing it the way you want.

You give a type a constructor when you want to force users to call a constructor to construct it. When you don't, you just use factory functions.

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