C ++错误：“ operator =”不匹配 [英] C++ Error: No match for 'operator='

问题描述

将值分配给数组时出现问题。我创建了一个名为库房的课程。我创建了另一个名为 TradingBook 的类，该类包含一个 Treasury 的全局数组，可以从其中的所有方法访问该数组。 TradingBook 。这是我的TradingBook和Treasury头文件：

Having a problem when assigning a value to an array. I have a class I created called Treasury. I created another class called TradingBook which I want to contain a global array of Treasury that can be accessed from all methods in TradingBook. Here is my header files for TradingBook and Treasury:

class Treasury{
public:
    Treasury(SBB_instrument_fields bond);
    Treasury();
    double yieldRate;
    short periods;
};


class TradingBook
{
public:
    TradingBook(const char* yieldCurvePath, const char* bondPath);
    double getBenchmarkYield(short bPeriods) const;
    void quickSort(int arr[], int left, int right, double index[]);

    BaseBond** tradingBook;
    int treasuryCount;
    Treasury* yieldCurve;
    int bondCount;
    void runAnalytics(int i);
};

这是我得到错误的主要代码：

And here is my main code where I'm getting the error:

TradingBook::TradingBook(const char* yieldCurvePath, const char* bondPath)
{
    //Loading Yield Curve
    // ...
    yieldCurve = new Treasury[treasuryCount];

    int periods[treasuryCount];
    double yields[treasuryCount];
    for (int i=0; i < treasuryCount; i++)
    {
        yieldCurve[i] = new Treasury(treasuries[i]);
        //^^^^^^^^^^^^^^^^LINE WITH ERROR^^^^^^^^^^^^^^
    }
}

我遇到了错误：

在'yieldCurve [i] = new Treasury（treasuries [i]）行上的'operator ='没有匹配项； '

No match for 'operator=' on the line 'yieldCurve[i] = new Treasury(treasuries[i]);'

有任何建议吗？

推荐答案

这是因为 yieldCurve [i] 的类型为库房和 new Treasury（treasuries [i]）; 是指向 Treasury 对象的指针。因此，您的类型不匹配。

That's because yieldCurve[i] is of type Treasury, and new Treasury(treasuries[i]); is a pointer to a Treasury object. So you have a type mismatch.

尝试更改此行：

yieldCurve[i] = new Treasury(treasuries[i]);

为此：

yieldCurve[i] = Treasury(treasuries[i]);

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