GCC -Wunused功能不起作用（但其他警告正在起作用） [英] GCC -Wunused-function not working (but other warnings are working)

问题描述

我试图通过使用GCC的 -Wunused-function 标志在代码库中找到未使用的函数。

I'm trying to find unused functions in my codebase by using GCC's -Wunused-function flag.

如我所料，用 gcc -Wall -Wunused-function main.cpp 编译以下代码会显示未使用变量警告：

As I would expect, compiling the below code with gcc -Wall -Wunused-function main.cpp prints an unused variable warning:

warning: unused variable ‘x’ [-Wunused-variable]

但是，编译器不会给出未使用功能警告。
如何使GCC注意到未使用的函数 foo（）？

However, the compiler doesn't give an unused-function warning. What do I have to do to make GCC notice the unused function foo()?

// main.cpp

void foo(){ } //should (but doesn't) trigger 'unused function' warning

int main (int argc, char **argv){
    int x; //correctly triggers 'unused variable' warning
    return 0;
}

请记住，我确实要未使用的功能警告。这不是不是如何摆脱警告问题。

Remember, I do want unused function warnings. This is not a "how do I get rid of warnings" question.

推荐答案

文档：

-Wunused-function：当声明了静态函数但未定义或未使用非内联静态函数时发出警告。此警告是由-Wall启用的
。

-Wunused-function: Warn whenever a static function is declared but not defined or a non-inline static function is unused. This warning is enabled by -Wall.

如您所见，您已经定义并声明了一个非静态的功能。此外，您的函数没有被内联（您需要使用 -O3 优化）。

As you can see, you've defined and declared a non-static function. Also your function isn't being inlined(for which you need to use -O3 optimization).

我不确定您要的内容是否存在于gcc中。 :-)但是它是开源的..也许您可以实现它？

I am not sure what you're asking for exists in gcc, as of yet. :-) But its open source.. maybe you can implement it?

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