如何编写python方法来计算列表字典的所有组合？ [英] How can I write a python method to compute all combinations of a dict of lists?

问题描述

我有一个任意的python字典 x ，这样每个键的值本身就是一个列表。下面是一个示例：

I have an arbitrary python dictionary x such that the values of each key is itself a list. Here is an example:

x = {"first_name": ["Mahmoud", "Pei-chi"], "second_name": ["Abadi", "Yao"]}

给出 x 我想写一个方法来计算字典列表，这样每个字典都具有与x相同的键，但是值分别是单个列表元素的组合。因此，在这种情况下，结果应为：

Given x I would like write a method that computes a list of dictionaries such that each dictionary has the same keys as x but the values are each combination of individual list element. So in this case, the result should be:

[{"first_name": "Mahmoud", "second_name": "Abadi"}, 
 {"first_name": "Mahmoud", "second_name": "Yao"}, 
 {"first_name": "Pei-chi", "second_name": "Abadi"}, 
 {"first_name": "Pei-chi", "second_name": "Yao"}]

我该怎么办？字典 x 可以具有任意数量的具有任意名称的键。

How can I do it? The dictionary x may have any arbitrary number of keys with arbitrary names.

推荐答案

您可以发布以下列表信息。

You can issue the following list comprehension.

result = [dict(zip(x.keys(), t)) for t in product(*x.values())]

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