Django REST Framework-将额外的参数传递给动作 [英] Django REST Framework - pass extra parameter to actions

问题描述

我正在使用 Django 2.0 和 Django REST Framework

我已经创建了一种从数据库删除特定对象的操作方法

I have created an action method to delete particular object from database

contacts / views.py

class ContactViewSet(viewsets.ModelViewSet):
    serializer_class = ContactSerializer
    permission_classes = (IsAuthenticated, AdminAuthenticationPermission,)

    # others actions goes here

    @action(methods=['delete'], detail=False, url_path='delete_phone/<phone_pk>/')
    def delete_phone(self, request, pk=None):
        contact = self.get_object()
        print(contact)
        print(pk)
        print(self.kwargs['phone_pk'])
        return Response({'status': 'success'})

应用/urls.py

router.register(r'contacts', ContactViewSet, 'contacts')

api_urlpatterns = [
    path('', include(router.urls)),
]

但是当我访问

DELETE: http://url/api/contacts/delete_phone/1/

它给出了页找不到错误。

It gives page not found error.

在错误页面中，有尝试过的网址格式

api/ ^contacts/delete_phone/<phone_pk>//$ [name='contacts-delete-phone']
api/ ^contacts/delete_phone/<phone_pk>\.(?P<format>[a-z0-9]+)/?$ [name='contacts-delete-phone']

推荐答案

使用 drf-nested-routers

对于那些需要它的人，安装插件并配置 urls.py

For those who need it, install the plugin and configure urls.py

from rest_framework_nested import routers

router = routers.SimpleRouter()
router.register(r'contacts', ContactViewSet, 'contacts')
contact_router = routers.NestedSimpleRouter(router, r'contacts', lookup='contact')
contact_router.register(r'phone_number', ContactPhoneNumberViewSet, base_name='contact-phone-numbers')

api_urlpatterns = [
    path('', include(router.urls)),
    path('', include(contact_router.urls))
]

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