以特定周期宽度绘制Cosx [英] Draw Cosx with specific period width

问题描述

我如何绘制宽度为100且高度为50的Cosx周期？

how can i draw a period of Cosx with width =100 and height 50?

我最近的代码很难控制它们：（

my recent code is very hard to control them :(

// this to find y with each x to draw Cos
for (int i = 0, j = 0; i < 50; i += 1, j++)
{
    int y = (int)((Math.Cos((double)i * height/10F * Math.PI / cy) + 1.0) * (cx - 1) / widtd/10F);
    poi.SetValue(new Point(i, y),j);  // poi is an aray of point
}

推荐答案

基于OP的最后评论，我认为宽度是指一个句点，因此计算点幅度为 amp 且周期为 的余弦函数的形式如下：

Based on OP's last comment I assume "width" means a single period. Therefore to calculate the points of a cosine function with amplitude amp and a period of period looks like this:

int amp = 50, period = 100;
Point[] poi = new Point[period];
for (int x = 0; x < period; x++)
{
    int y = (int)(amp * Math.Cos(x * 2 * Math.PI * (1.0 / period)));
    poi[x] = new Point(x, y);
}

N提示这是 1：1计算，即一个点是一个像素。

Note that this is a "1:1" calculation, i.e. one point is one pixel.

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