libgdx Shaperenderer line .. 如何绘制具有特定宽度的线 [英] libgdx Shaperenderer line .. How to draw line with a specific width

问题描述

我正在尝试使用 libgdx 形状渲染器绘制一条特定宽度的线.我关注了这个 链接

I am trying to draw a line of specific width using libgdx shape renderer. I followed this link

问题是如果我指定更多的线宽，即超过 9，它不会显示增加的宽度.超过 9 时，我指定 20 或 100 像素，结果与 9 相同

The problem is if i specify more line width i.e more than 9 it does not show increased width. More than 9 either i specify 20 or 100 pixels it will have the same result as 9

shapeRenderer.begin(ShapeType.Line);
    shapeRenderer.line(50, 70, 0, 50, 200, 0, Color.BLUE, Color.RED);
    int lineWidth = 20; // pixels
    Gdx.gl10.glLineWidth(lineWidth / camera.zoom);
     shapeRenderer.end();

谢谢沙克尔

推荐答案

查询支持的宽度范围和大小之间的差异范围内支持的宽度，使用参数调用 glGetGL_ALIASED_LINE_WIDTH_RANGE、GL_SMOOTH_LINE_WIDTH_RANGE 和GL_SMOOTH_LINE_WIDTH_GRANULARITY.

To query the range of supported widths and the size difference between supported widths within the range, call glGet with arguments GL_ALIASED_LINE_WIDTH_RANGE, GL_SMOOTH_LINE_WIDTH_RANGE, and GL_SMOOTH_LINE_WIDTH_GRANULARITY.

参考

为了避免特定于设备的行为，我使用了四边形.从一个小纹理中绘制一个 1x1 的正方形，然后定位、缩放(取决于您要绘制的线条的宽度和高度)、颜色和旋转它.

To avoid device specific behavior, I use a quad instead. Draw a 1x1 square from a small texture and then position, scale (depending on the width and height of the line you wanted to draw), color, and rotate it.

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