如何将整数转换为LARGE_INTEGER [英] How to convert an Integer to LARGE_INTEGER
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问题描述
如何将整数转换为LARGE_INTEGER?
How do i convert an integer to LARGE_INTEGER?
例如,当我想立即触发计时器时:
For example, when I want to trigger a timer immediately:
LARGE_INTEGER zero;
zero.QuadPart = 0;
KeSetTimer(pTimer, zero, pDpc);
有什么方法可以将0转换为LARGE_INTEGER?因此我可以改为:
Is there any way to convert 0 to LARGE_INTEGER? So I could do this instead:
KeSetTimer(pTimer, (SomeType)0, pDpc);
我尝试过:
KeSetTimer(pTimer, (LARGE_INTEGER )0, pDpc);
但这不起作用。我已经用Google搜索,但是找不到任何帮助。
But it doesn't work. I have Googled, but couldn't find any help.
推荐答案
LARGE_INTEGER
是结构
。
无法将值强制转换为结构类型。
LARGE_INTEGER
is a struct
.
It is not possible to cast a value to a struct type.
您需要创建该结构的实例并根据需要设置其字段。
You need to create an instance of the struct and set its fields as needed.
例如:
LARGE_INTEGER intToLargeInt(int i) {
LARGE_INTEGER li;
li.QuadPart = i;
return li;
}
然后可以像这样使用它:
You can then use it like this:
KeSetTimer(pTimer, intToLargeInt(0), pDpc);
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