Bash脚本，用于搜索目录并将文件移动到新目录，删除所有副本 [英] Bash script for searching directory and moving files to a new directory, deleting any copies

问题描述

我有一个充满备份数据的2TB硬盘，其中包括数百部电影，由于相同HD的连续备份，其中大多数已被复制了几次.硬盘驱动器按备份文件夹列表进行组织，每个备份都包含一个电影文件夹，其中包含备份时笔记本电脑HD上的所有电影.

I have a 2TB hard drive full of backed up data, including hundreds of movies, most of which have been copied several times due to sequential back-ups of the same HD. The hard drive is organized as a list of back-up folders, and every back-up contains a movies folder that has all the movies that were on my laptop HD at the time of the back-up.

我想创建一个新的电影文件夹，并将所有电影从每个电影"子文件夹移至新的文件夹，并确保不要将同一部电影两次移动.如果我想通过Bash进行所有操作，该怎么办?

I'd like to create a new movies folder and move all movies from every "movies" subfolder into the new one, making sure not to move the same movie twice. How can I go about this if I want to do everything via Bash?

推荐答案

假定电影在各个文件夹中的每个副本都具有相同的名称，并且都具有相同的扩展名(比如说.divx)，则可以使用find找到它们并将它们复制到其他文件夹，然后删除旧文件夹.

Assuming that each copy of a movie in various folders has the same name and all have the same extension, let's say .divx, you can use find to find them and copy them to a different folder and then delete the old folders.

find / -iname "*.divx" -type f -print0 | xargs -0 -I '{}' mv "{}" /path/to/new_folder/

或者，您可以循环浏览所有文件并将其复制到new_folder(仅当它们不存在时).如果已经存在，请删除其他副本.像这样:

Or you can loop through all the files and copy them to new_folder only if they are not already present. If already present, delete other copies. Something like this:

for file in $(find . -iname "*.divx" -type f)
do
filename=$(basename ${file})
if [ ! -f ./movie/${filename} ]; then
    mv ${file} ./movie/${filename}
else
    rm ${file}
fi
done

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