在find和xarg组合上需要计数器 [英] Need counter on find and xarg combo

问题描述

所以我有这段代码:

find cobacoba -type f | xargs -n 5 bash -c 'a=(${0} ${1} ${2} ${3} ${4}); echo "File #: ${a[*]}";'

希望结果:

File #: cobacoba/1.3 cobacoba/1.6 cobacoba/1.q cobacoba/1.5
File #: cobacoba/1.1 cobacoba/1.q2 cobacoba/1.q23 cobacoba/1.4
File #: cobacoba/1.2

我想将#替换为计数器，例如1、2、3，依此类推...

I would like to replace # with counter, like 1, 2, 3, so on...

推荐答案

您可以使用awk对输出进行后处理，以将#替换为行号:

You can postprocess your output with awk to replace # with the line number:

find cobacoba -type f |
   xargs -n 5 bash -c 'a=(${0} ${1} ${2} ${3} ${4}); echo "File #: ${a[*]}";' |
   awk '{gsub("#", NR, $0); print}'

此方法的来源: Sed替换模式为行号

PS:有人可能会认为我应该将问题标记为重复，而不是回答，但我认为即使解决方案相同，上下文也足以保证给出答案.

PS: one might argue I should have flagged the question as a duplicate instead of answering, but I think the context is sufficiently different to warrant an answer even if the solution is the same.

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