获取从Flask URL解析的变量 [英] Get variables parsed from Flask URL

问题描述

假设我有一条带有可变部分的简单路线:

Suppose I have a simple route with a variable part:

@app.route('/post/<int:post_id>')
def show_post(post_id):
    return 'Post %d' % post_id

现在我要注册一个上下文处理器

Now I want to register a context processor that

1. 仅在以post_id作为参数调用视图函数时运行
2. 以某种方式可以访问post_id，而不必通过例如重新重新解析URL. re.match

1. Only runs when the view function is called with post_id as a parameter
2. somehow has access to post_id, without having to re-parse the URL all over again with e.g. re.match

本质上:

@app.context_processor
def foo():
    post_id = ???
    return {'bar': some_function(post_id)}

如果我可以从上下文处理器访问在本示例 中传递给show_post的**kwargs，则可以执行此操作，但是我找不到这样做的方法.有什么想法吗?

If I could access the **kwargs passed to show_post in this example from the context processor I could do it, but I've found no way to do that. Any ideas?

推荐答案

使用 request.view_args :

@app.context_processor
def provide_foo():
    if "post_id" in request.view_args:
        post_id = request.view_args["post_id"]
        return {"bar": some_function(post_id)}

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