获取从 Flask URL 解析的变量 [英] Get variables parsed from Flask URL

问题描述

假设我有一个带有可变部分的简单路由:

Suppose I have a simple route with a variable part:

@app.route('/post/<int:post_id>')
def show_post(post_id):
    return 'Post %d' % post_id

现在我想注册一个上下文处理器

Now I want to register a context processor that

1. 仅在以post_id为参数调用视图函数时运行
2. 以某种方式可以访问 post_id，而无需重新解析 URL，例如重新匹配

1. Only runs when the view function is called with post_id as a parameter
2. somehow has access to post_id, without having to re-parse the URL all over again with e.g. re.match

本质上:

@app.context_processor
def foo():
    post_id = ???
    return {'bar': some_function(post_id)}

如果我可以访问传递给 show_post 的 **kwargs 在这个例子中来自上下文处理器我可以做到，但我'我发现没有办法做到这一点.有什么想法吗?

If I could access the **kwargs passed to show_post in this example from the context processor I could do it, but I've found no way to do that. Any ideas?

推荐答案

使用 request.view_args:

@app.context_processor
def provide_foo():
    if "post_id" in request.view_args:
        post_id = request.view_args["post_id"]
        return {"bar": some_function(post_id)}

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