调用在golang中作为接口变量接收的函数 [英] Invoke a function which is received as an interface variable in golang

问题描述

我有一个与以下代码相似的代码

I have a code which is similar to the following

package main

import "fmt"

func PrintThis(arg string) {
    fmt.Printf("I'm printing %s", arg)
}

func PrintThisAndThat(arg1, arg2 string) {
    fmt.Printf("Now printing %s and %s", arg1, arg2)
}

func Invoke(fn interface{}, args ...string) {
    //fn(args...)
}

func main() {
    Invoke(PrintThis, "foo")
    Invoke(PrintThisAndThat, "foo", "bar")
}

这不是实际的生产代码，但这是简化的版本.

This is not the actual production code, but this is a simplified version.

问题:-如果我取消注释//fn(args...)行，则会出现编译错误prog.go:14: cannot call non-function fn (type interface {})

Question :- If I uncomment the line //fn(args...) I get a compile error prog.go:14: cannot call non-function fn (type interface {})

如何执行通过Invoke()函数作为参数接收的函数?

How do I execute the function which is received as the argument tho the Invoke() function?

实现此目标的正确方法是什么?

What is the right way to achieve this?

推荐答案

您使用 或reflect.Value的 CallSlice 方法进行调用作为一个功能.与所有reflect.Value方法一样，这种恐慌是fn是错误的类型.

You use the Call or CallSlice methods of the reflect.Value to call it as a function. As with all reflect.Value methods, this panics is fn is the wrong type.

func Invoke(fn interface{}, args ...string) {
    v := reflect.ValueOf(fn)
    rargs := make([]reflect.Value, len(args))
    for i, a := range args {
        rargs[i] = reflect.ValueOf(a)
    }
    v.Call(rargs)
}

http://play.golang.org/p/xGmNLDcLL_

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