带有glm向量的struct中没有合适的默认构造函数 [英] No appropriate default constructor available in struct with glm vectors

问题描述

在.h中:

enum collisionType {AB, BA, AoverB, AunderB};

struct Collision {
public:
    collisionType type;
    glm::vec2 point1;
    glm::vec2 point2;

    Collision(enum collisionType, glm::vec2, glm::vec2);
};

<.cpp中的

:

in .cpp:

Collision::Collision(enum collisionType collisType, glm::vec2 p1, glm::vec2 p2) : type(collisType), point1(p1), point2(p2)
{

}

使用

std::vector<Collision> collisions;

glm::vec2 point1(11.0, 12.0);
glm::vec2 point2(12.0, 13.0);

collisions.push_back(Collision(AoverB, point1, point2));

遇到错误C2512:碰撞":没有合适的默认构造函数，为什么?

Getting error C2512: 'Collision' : no appropriate default constructor available, why?

推荐答案

您可以在此处阅读 类型T非常适合std::vector的要求.
此处未列出default-constructible.

You can read here the requirements for a type T to be well suited for std::vector.
Default-constructible is not listed there.

我还尝试编译此最小代码示例，其中X没有默认构造函数，并且可以使用MSVC很好地编译:

I also tried compiling this minimal code sample, in which X doesn't have a default constructor, and it compiles fine with MSVC:

#include <vector>

struct X {
    X(int a, int b) : A(a), B(b) {}
    int A;
    int B;
};

int main() {
    std::vector<X> v;
    v.push_back(X(10,20));
}

因此，问题必须出在代码的其他地方.

So, the problem must be elsewhere in your code.

无论如何，您可能想要添加一个不带参数的构造函数，以使Collission类默认可构造"，并使编译器满意:

Anyway, you may want to add a constructor with no arguments to make your Collission class "default-constructible", and make the compiler happy:

struct Collision {

    // Default constructor.
    // Initialize data members to some init values.
    Collision() {
        ...
    }

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PS 请注意，C ++中的struct等同于class { public: ...，因此您可以在代码中省略public:行:这是通过使用关键字struct来暗示的.

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PS Note that struct in C++ is equivalent to class { public: ..., so you can omit the public: line in your code: it's implied by the use of the keyword struct.

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