正则表达式中的grep辅音 [英] grep consonants in regular expression

问题描述

我想使用grep查找具有特定数量辅音的单词.但是，使用以下命令将给我连续的辅音，如何修改命令以使非连续的辅音也可以?

I want to use grep to find words that have a specific number of consonants. But using the following command will give me consecutive consonants, How do i modify the command so that non-consecutive consonants are also OK?

grep -iE '[^aeiouy]{3}' filename

推荐答案

grep -iP '^(?=(.*[^aeiouy]){3}).*$' filename

您可以尝试这样做.这将选择在字符串中任何位置至少具有3个辅音的单词.请使用P或perl模式.

You can try this.This will select words which have at least 3 consonants anywhere in the string.Use P or perl mode.

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