Python IMAPLIB HTML正文解析 [英] Python IMAPLIB HTML body parsing
问题描述
因此,基本上,我有一个连续运行的脚本,当一封新电子邮件到达收件箱中,其中包含主题中的特定文本时,它将从电子邮件中获取信息.我只设法从电子邮件中提取主题,但是无论如何尝试,我都无法获得它的电子邮件正文,我相信电子邮件正文是HTML格式的,所以我尝试使用BeautifulSoup来解析正文但这根本不起作用.请帮忙!!! :(这是我到目前为止所拥有的:
so basically i have this script that runs continuously and when a new email arrives in the inbox with specific text in the subject, it grabs information from the email. I have only managed to get it to pull the subject from the email but I cant get it do get the body of the email no matter what I try, I believe the email body is in HTML so i attempted to use BeautifulSoup to parse the body but that doesnt work at all. Please help!!! :( Here is what i have so far:
import email
import imaplib
from bs4 import BeautifulSoup
import time
import sys
username = 'xxx.xxx@xxx.xx'
password = 'xxxxxx'
mail = imaplib.IMAP4_SSL('imap-mail.outlook.com')
(retcode, capabilities) = mail.login(username, password)
mail.list()
n=0
while True:
mail.select('inbox')
(retcode, messages) = mail.search(None, 'UNSEEN', '(SUBJECT "xxxxxxx-
")', '(FROM "xx.xx@xxxx.xx")')
if retcode == 'OK':
for num in messages[0].split():
n=n+1
print('Processing Email ' + str(n))
typ, data = mail.fetch(num, '(RFC822)')
for response_part in data:
if isinstance(response_part, tuple):
original = email.message_from_bytes(response_part[1])
print("Subject: " + original['Subject'])
typ, data = mail.store(num,'+FLAGS','\\Seen')
time.sleep(120)
推荐答案
注释:
imap.fetch
返回的"body"通常是bytes
,而不是引发异常的字符串
Comment: The "body" returned by
imap.fetch
are usuallybytes
, not a string, which throws an exception
更改为:
msg = email.message_from_bytes(body)
问题:我无法理解电子邮件的正文
Question: I cant get it do get the body of the email
例如:
import email, imaplib
username = 'xxx.xxx@xxx.xx'
password = 'xxxxxx'
imap = imaplib.IMAP4_SSL('imap-mail.outlook.com')
imap.login(username, password)
imap.select("inbox")
resp, items = imap.search(None, "(UNSEEN)")
for n, num in enumerate(items[0].split(), 1):
resp, data = imap.fetch(num, '(RFC822)')
body = data[0][1]
msg = email.message_from_string(body)
content = msg.get_payload(decode=True)
print("Message content[{}]:{}".format(n, content))
这篇关于Python IMAPLIB HTML正文解析的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!