Lua:将文件包含在同一目录中 [英] Lua: Include file in the same directory

问题描述

我正在使用 IMAPFilter ，我想将全局配置保留在公共存储库，同时将本地(和秘密)配置保留在单独的文件中.因此，我从某个目录运行imapfilter，它包含〜/.imapfilter/config.lua，而那个应该包含./config_local.lua，其中.".是 config.lua 的目录，不是 shell $PWD的目录或imapfilter的位置.到目前为止，这是我尝试过的事情:

I'm using IMAPFilter, and I'd like to keep my global configuration in a public repository, while keeping the local (and secret) configuration in a separate file. So I'm running imapfilter from some directory, it includes ~/.imapfilter/config.lua, and that should include ./config_local.lua, where "." is the directory of config.lua, not the shell $PWD or the location of imapfilter. Here's what I've tried so far:

require "config_local"
require "./config_local"

绝对路径有效:

dofile(os.getenv("HOME") .. "/.imapfilter/config_local.lua")

不太优雅，但至少与cron兼容.

Not very elegant, but at least it's compatible with cron.

推荐答案

将路径添加到package.path.

类似这样的东西(未经测试):

Something like this (not tested):

package.path = package.path .. ";" .. os.getenv("HOME") .. "/.imapfilter/?.lua"

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