如何避免使用直接值初始化进行最烦人的解析 [英] How can I avoid most vexing parse with direct value initialization
问题描述
在阅读大多数令人讨厌的解析后,我了解以下代码也很含糊
After read Most vexing parse, I understand the following code is also ambigous
T x();
一方面,它可以解释为一个函数声明,该声明返回一个对象T
;另一方面,它也可以解释为一个变量定义,并且对象x
是
In one hand, it can be interpreted as a function declaration which returns an object of T
, on the other hand, it can also be interpreted as a variable definition, and object x
is value-initialized.
我知道我可以像下面的代码一样使用统一初始化来避免冲突
I understand I can use uniform initialization like the following code to avoid confliction
T x{};
我还理解T
是否是(C ++ 11之前的非POD)类,并且以下默认初始化实际上等于值初始化
I also understand if T
is a (non-POD before C++11) class and the following default initialization actually equals value initialization
T x;
同时,如果不需要直接初始化,我们可以使用复制初始化
Meanwhile, if direct initialization is not necessary, we can use copy initialization
T x = T();
但是,我认为这三种解决方案中的任何一种都有其局限性.我知道是否有一些论点,我也可以使用一对额外的括号
Howerver, I think any of the three solutions are have their limitation. I know if there are some arguments, I can also use an extra pair of parentheses
T x((arg));
我想采用这种策略,但是以下代码不起作用
I want to adopt this strategy, but the following code does not work
T x(());
所以我想知道是否存在一些更好的直接值初始化解决方案?
So I am wondering is there are some better solutions with direct value initialization?
推荐答案
使用复制初始化,并依靠c ++ 17保证复制省略.
Use copy initialisation and rely on c++17's guarantee that copy elision will happen.
例如:
struct Foo
{
Foo() = default;
Foo(Foo const&) = delete;
};
int main()
{
auto f = Foo();
}
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