如何在不重复其签名的情况下强制模板化函数的特定实例化? [英] How do I force a specific instantiation of a templated function without repeating its signature?

问题描述

对于某些特定的模板参数，我需要实例化具有长签名的模板化函数foo().

I need to instantiate a templated function foo() with a long signature, for some specific template arguments.

我只是阅读了此问题的答案，该答案本质上是建议复制函数签名但设置特定参数.我想以某种方式避免这种情况.有什么合理的方法来实现这一目标?例如可以让我写东西的东西

I just read the answers to this question which essentially suggest copying the function signature but setting the specific arguments. I want to avoid that somehow. What is a reasonable way to achieve this? e.g. something which would allow me to write

INSTANTIATE(foo, template_arg1, template_arg2);

或者也许

MyFunctionType<template_arg1, template_arg2> foo;

仅出于说明目的，假设这是foo的代码:

Just for illustrative purposes, suppose this is the code for foo:

template<typename T, int val>
unsigned foo(
    T bar,
    SomeType baz1,
    SomeOtherType baz2,
    YetAnotherType you_catch_the_drift) 
{ 
    /* some code here */ 
}

推荐答案

您可以简单地定义一个宏:

You can simply define a macro:

#define INSTANTIATE_FOO(T, val) \
template \
unsigned foo<T, val>( \
    T bar, \
    SomeType baz1, \
    SomeOtherType baz2, \
    YetAnotherType you_catch_the_drift);

并以以下方式使用它:

INSTANTIATE_FOO(int, 0)

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