C#中的乘积方法 [英] Product method in c#

问题描述

我正在使用python，并且正在将代码实现为c#，并且在python中有方法"product"，有人知道c#中是否存在类似的东西?如果不是，也许有人可以让我了解如何自己编写此功能?

I am working with python, and I am implementing my code to c# and in python there is method "product", anyone knows if there is something similar in c#? if not maybe someone can put me on a track of how to write this function by myself?

产品示例:

a=[[[(1, 2), (3, 4)], [(5, 6), (7, 8)], [(9, 10), (11, 12)]], [[(13, 14), (15, 16)]]]

b= product(*a)

输出:

([(1, 2), (3, 4)], [(13, 14), (15, 16)])
([(5, 6), (7, 8)], [(13, 14), (15, 16)])
([(9, 10), (11, 12)], [(13, 14), (15, 16)])

推荐答案

假设您的意思是

Assuming you mean itertools.product (it looks like it from the example given):

public static List< Tuple<T, T> > Product<T>(List<T> a, List<T> b)
    where T : struct
{
    List<Tuple<T, T>> result = new List<Tuple<T, T>>();

    foreach(T t1 in a)
    {
        foreach(T t2 in b)
            result.Add(Tuple.Create<T, T>(t1, t2));
    }

    return result;
}

n.b. struct在这里意味着T必须是值类型或结构.如果需要抛出诸如List之类的对象，但要注意潜在的引用问题，请将其更改为class.

n.b. struct here means that T must be a value type or a structure. Change it to class if you need to throw in objects such as Lists, but be aware of potential referencing issues.

然后作为驱动程序:

List<int> listA = new List<int>() { 1, 2, 3 };
List<int> listB = new List<int>() { 7, 8, 9 };

List<Tuple<int, int>> product = Product<int>(listA, listB);
foreach (Tuple<int, int> tuple in product)
    Console.WriteLine(tuple.Item1 + ", " + tuple.Item2);

输出:

1, 7
1, 8
1, 9
2, 7
2, 8
2, 9
3, 7
3, 8
3, 9

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