忽略数组顺序时匹配响应 [英] match response while ignoring array order

问题描述

给出以下响应:

* def resp = {"a":[{"c": 2},{"c": 1}, {"c":3}], "b":[6,5,4]}

无论顺序数组在哪里，我都想匹配它.

I want to match it no matter the order arrays are in.

我知道我可以使用contains指令来做到这一点，但是我认为这需要我执行多种匹配模式，例如:

I know I could do it with contains directive but I think that would require me to do multiple match patterns like:

  * match resp.a.[*].c contains [3,2,1]
  * match resp.b contains [5,4,6]

是否存在诸如全局配置之类的东西来全部忽略数组顺序，还是我必须滚动包含对象?

Is there something like global config to ignore array order all together or do I have to roll with contains?

推荐答案

以下工作.例如，您也可以指定数组的大小.

The following works. You could also specify the size of the array if you want for example.

    * def response = {"a":[2,1,3], "b":[6,5,4]}
    * match response.a contains [3,2,1]
    * match response.b contains [5,4,6]
    * match response == {"a": "#[] #? _ <4, _ >0", "b": "#[] #? _ <7, _ >3"}

编辑以适合您更详细的情况:

Edit to match your more detailed case :

    * def resp = {"a":[{"c": 2},{"c": 1}, {"c":3}], "b":[6,5,4]}
    * def inside = {"c" : "#number"}
    * def schema = { "a": "#[] #(inside)", "b": "#[] #number" }
    * match resp == schema

这篇关于忽略数组顺序时匹配响应的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！