正则表达式以匹配两个字符之间的多个数字组 [英] Regex to match multiple number groups between two characters

问题描述

我有一个类似于以下内容的字符串:

I have a string that looks like the following:

<@399969178745962506> hello to <@!104729417217032192>

我有一本包含两者的字典，如下所示:

I have a dictionary containing both that looks like following:

{"399969178745962506", "One"},
{"104729417217032192", "Two"}

我的目标是将< @ 399969178745962506> 替换为该数字键的值，本例中为 One

My goal here is to replace the <@399969178745962506> into the value of that number key, which in this case would be One

Regex.Replace(arg.Content, "(?<=<)(.*?)(?=>)", m => userDic.ContainsKey(m.Value) ? userDic[m.Value] : m.Value);

我当前的正则表达式如下:(?< =<)(.*?)(?=>)仅匹配< 和> ，在这种情况下将同时保留 @ 399969178745962506 和 @ !! 104729417217032192

My current regex is as following: (?<=<)(.*?)(?=>) which only matches everything in between < and > which would in this case leave both @399969178745962506 and @!104729417217032192

我不能只是忽略 @ 符号，因为每次都不存在！符号.因此，最好只获取具有 \ d +

I can't just ignore the @ sign, because the ! sign is not there every time. So it could be optimal to only get numbers with something like \d+

我需要弄清楚如何只获取< 和> 之间的数字，但我一生都无法弄清楚如何实现.

I need to figure out how to only get the numbers between < and > but I can't for the life of me figure out how.

非常感谢您的帮助！

推荐答案

要从给定格式中仅提取数字，请使用以下正则表达式模式:

To extract just the numbers from you're given format, use this regex pattern:

(?<=<@|<@!)(\d+)(?=>)

查看它的实际效果: https://regexr.com/3j6ia

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