使用正则表达式查找不在两个字符之间的文本 [英] Use regex to find text NOT between two characters

问题描述

我有一个单词字符串，其中每个单词由换行符分隔.我使用 RegEx 替换在常见前缀和后缀周围插入 '{' 和 '}' 字符.结果如下:

I have a single string of words, in which each word is separated by a newline character. I've used RegEx replacements to insert '{' and '}' characters around common prefixes and suffixes. The result looks like this:

{con}descens{ion}
lumberjack
tim{ing}
{tox}{icity}
fish
{dis}pel

我想弄清楚的是如何对这个字符串执行 RegEx 替换，它只会匹配 'not 之间的文本/strong>' 和 '}' 字符.我有进一步的替换，每次我都会在匹配项周围放置{"和}"字符；我只是不想在执行新替换时匹配以前的替换(或其中的部分).例如，我知道如何匹配not '{'"，但我不知道如何匹配not between '{' and '}'"

What I'm trying to figure out is how I can perform a RegEx replace on this string that will only match text not between the '{' and '}' characters. I have further replacements to make, and each time I do, I'll be placing the '{' and '}' characters around the matches; I just don't wan't previous replacements (or pieces thereof) to be matched when performing new replacements. I know how to match "not '{'", for example, but I don't know how to match "not between '{' and '}'"

从正确的角度来看，此处的下一个替换操作示例是将所有 'n' 字符替换为 '7' 个字符.在这种情况下，字符串的第一行{con}descens{ion}"应该变成{con}desce{7}s{ion}"而不是{co{7}}desce{7}s{io{7}}";根据这些标准，其他词将保持不变.

To put it into perspective, an example next replacement operation here would be to to replace all 'n' characters with '7' characters. In this case, the first line of the string, "{con}descens{ion}", should become "{con}desce{7}s{ion}" and not "{co{7}}desce{7}s{io{7}}"; the other words would remain the same based on these criteria.

有什么建议吗?

推荐答案

假设你的花括号总是平衡的，你可以在这里使用 Negative Lookahead.

Assuming your curly braces will always be balanced, you can use a Negative Lookahead here.

[a-zA-Z]+(?![^{]*\})

注意:这仅匹配 A 到 Z 范围的字符，如果单词将包含空格或您有其他字符需要允许或不确定输入的类型，您可以在此处使用否定匹配.

Note: This only matches characters of the A to Z range, if words will include whitespace or you have other characters that need to be allowed or unsure of the type of input, you can use a negated match here.

[^}]+(?![^{]*\})

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