如何在Pygame中制作圆形表面 [英] how to make circular surface in pygame

问题描述

我需要创建一个具有边界圆的曲面.在该表面上绘制的任何内容在该边界圆之外均不可见.我曾尝试使用遮罩，地下，srcalpha等，但似乎无济于事.

我的尝试:

  w = ss.get_width()h = ss.get_height()透明=(255，255，255，0)不透明=(0，0，0，225)作物= pygame.Surface((w，h)，pygame.SRCALPHA，ss)crop.fill(透明)c =舍入(w/2)，舍入(h/2)r = 1pygame.gfxdraw.aacircle(crop，* c，r，OPAQUE)pygame.gfxdraw.filled_circle(crop，* c，r，OPAQUE)ss = crop.subsurface(crop.get_rect())App.set_subsurface(self，ss) 

以后...

  self.ss.fill(黑色)self.ss.blit(self.background，来源) 

背景是正方形图像.应该将其裁剪为圆形并在屏幕上呈现

基于Rabbid76的注释的解决方案:

  def draw_scene(self，temp = None):如果temp为None:temp = self.ss#1.在与窗口大小相同的表面上绘制所有内容(背景和场景).大小= temp.get_size()temp = pygame.Surface(大小)self.draw_cropped_scene(临时)#2.用白色圆圈创建表面.self.cropped_background = pygame.Surface(大小，pygame.SRCALPHA)self.crop()#3.在白色圆圈上涂抹前一个表面.self.cropped_background.blit(温度，来源，特殊标志= pygame.BLEND_RGBA_MIN)#4.把整个东西都抹在窗户上.self.ss.blit(self.cropped_background，来源)def draw_cropped_scene(自我，临时):App.draw_scene(自我，临时) 

crop()的示例实现为:

  def作物(个体):o，界限= self.boundsbounds = tr(bounds)#元组的圆形元素pygame.gfxdraw.aaellipse(self.cropped_background，* bounds，* bounds，OPAQUE)pygame.gfxdraw.filled_ellipse(self.cropped_background，* bounds，* bounds，OPAQUE) 

解决方案

背景是正方形图像.应该将其裁剪为圆形并在屏幕上呈现

您可以使用混合模式 BLEND_RGBA_MIN (请参见

  import pygamepygame.init()窗口= pygame.display.set_mode((250，250))背景= pygame.Surface(window.get_size())对于范围x中的x(5):对于范围(5)中的y:颜色=(255，255，255)如果(x + y)％2 == 0否则(255，0，0)pygame.draw.rect(背景，颜色，(x * 50，y * 50，50，50))大小= background.get_size()cropped_background = pygame.Surface(size，pygame.SRCALPHA)pygame.draw.ellipse(cropped_background，(255，255，255，255)，(0，0，* size))cropped_background.blit(背景(0，0)，special_flags = pygame.BLEND_RGBA_MIN)运行=真运行时:对于pygame.event.get()中的事件:如果event.type == pygame.QUIT:运行=错误window.fill(0)window.blit(cropped_background，(0，0))pygame.display.flip() 

---

另请参见如何填充pygame中窗口的某些圆形部分?

I need to create a surface that has a bounding circle. Anything drawn on that surface should not be visible outside that bounding circle. I've tried using masks, subsurfaces, srcalpha, etc., but nothing seems to work.

My attempt:

w = ss.get_width  ()
h = ss.get_height ()    
    
TRANSPARENT = (255, 255, 255,   0)
OPAQUE      = (  0,   0,   0, 225)
    
crop = pygame.Surface ((w, h), pygame.SRCALPHA, ss)
crop.fill (TRANSPARENT)
    
c = round (w / 2), round (h / 2)
r = 1
pygame.gfxdraw.     aacircle (crop, *c, r, OPAQUE)
pygame.gfxdraw.filled_circle (crop, *c, r, OPAQUE)
    
ss = crop.subsurface (crop.get_rect ())
App.set_subsurface (self, ss)

Later...

self.ss.fill (BLACK)
self.ss.blit (self.background, ORIGIN)

The background is a square image. It should be cropped into the shape of a circle and rendered on screen

Solution based on notes from Rabbid76:

def draw_scene (self, temp=None):
        if temp is None: temp = self.ss
        # 1. Draw everything on a surface with the same size as the window (background and scene).
        size = temp.get_size ()
        temp = pygame.Surface (size)
        self.draw_cropped_scene (temp)

        # 2. create the surface with the white circle.      
        self.cropped_background = pygame.Surface (size, pygame.SRCALPHA)
        self.crop ()

        # 3. blit the former surface on the white circle.
        self.cropped_background.blit (temp, ORIGIN, special_flags=pygame.BLEND_RGBA_MIN)
    
        # 4. blit the whole thing on the window.
        self.ss.blit (self.cropped_background, ORIGIN)

    def draw_cropped_scene (self, temp): App.draw_scene (self, temp)    

An example implementation of crop() is:

def crop (self):
        o, bounds = self.bounds
        bounds = tr (bounds) # round elements of tuple
        pygame.gfxdraw.     aaellipse (self.cropped_background, *bounds, *bounds, OPAQUE)
        pygame.gfxdraw.filled_ellipse (self.cropped_background, *bounds, *bounds, OPAQUE)

解决方案

The background is a square image. It should be cropped into the shape of a circle and rendered on screen

You can achieve this by using the blend mode BLEND_RGBA_MIN (see pygame.Surface.blit).

Create a transparent pygame.Surface with the same size as self.background. Draw a whit circle in the middle of the Surface and blend the background on this Surface using the blend mode BLEND_RGBA_MIN. Finally you can blit it on the screen:

size = self.background.get_size()
self.cropped_background = pygame.Surface(size, pygame.SRCALPHA)
pygame.draw.ellipse(self.cropped_background, (255, 255, 255, 255), (0, 0, *size))
self.cropped_background.blit(self.background, (0, 0), special_flags=pygame.BLEND_RGBA_MIN)

self.ss.fill(BLACK)
self.ss.blit(self.cropped_background, ORIGIN)

---

Minimal example:

import pygame
pygame.init()
window = pygame.display.set_mode((250, 250))

background = pygame.Surface(window.get_size())
for x in range(5):
    for y in range(5):
        color = (255, 255, 255) if (x+y) % 2 == 0 else (255, 0, 0)
        pygame.draw.rect(background, color, (x*50, y*50, 50, 50))

size = background.get_size()
cropped_background = pygame.Surface(size, pygame.SRCALPHA)
pygame.draw.ellipse(cropped_background, (255, 255, 255, 255), (0, 0, *size))
cropped_background.blit(background, (0, 0), special_flags=pygame.BLEND_RGBA_MIN)

run = True
while run:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False
        
    window.fill(0)
    window.blit(cropped_background, (0, 0))
    pygame.display.flip()

---

See Also How to fill only certain circular parts of the window in pygame?

这篇关于如何在Pygame中制作圆形表面的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！