为什么使用awk的数组输出顺序不正确? [英] Why the output of array using awk is not in right order?

问题描述

我有一个字符串:文件中的 Gatto piu bello anche cane .我正在使用awk拆分并将其放入数组.但是输出的顺序不正确.我的代码是:

I have a string: Gatto piu bello anche cane in file. I am using awk to split it and to put it into array. But the output is not in the right order. My code is:

while (getline < "'"$INPUTFILE"'") {
        text = $0;
}
split (text,text_arr," ");
for (i in text_arr) {
    print text_arr[i];
}

$ INPUTFILE 是带有该字符串的文件.

$INPUTFILE is file with that string.

但是此代码的输出是:

anche
cane
Gatto
piu
bello

我不知道出了什么问题.

I have no idea what's the problem.

推荐答案

awk 实际上没有索引数组.它只有关联数组.这意味着您不能以保证的顺序遍历键.但是， split 确实保证填充的数组将使用数字1到 n 作为键.这意味着您可以在正确的数值范围内进行迭代，并使用这些数值对数组进行索引.

awk doesn't actually have indexed arrays; it only has associative arrays. This means you can't iterate over the keys in an guaranteed order. split, however, does promise that the array it populates will use the numbers 1 through n as the keys. This means you can iterate over the correct numerical range, and use those to index the array.

for (i=1; i<=length(text_arr); i++) {
    print text_arr[i];
}

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