将数组的numpy数组转换为一个完整的numpy数组 [英] Converting numpy arrays of arrays into one whole numpy array

问题描述

我想将我的数组数组变成一个数组.来自类似

I want to turn my array of array into just a single array. From something like :

array([ array([[0, 0, 0, ..., 1, 0, 0],
       [0, 1, 0, ..., 0, 0, 0],
       [0, 0, 0, ..., 2, 0, 0],
       ..., 
       array([[0, 0, 0, ..., 0, 0, 0],
       [0, 0, 0, ..., 0, 0, 0],
       [0, 0, 0, ..., 8, 0, 2],
       ..., 
       [0, 0, 0, ..., 0, 0, 0],
       [1, 0, 0, ..., 0, 0, 0],
       [0, 0, 0, ..., 1, 0, 0]], dtype=uint8)], dtype=object)

大小为(10，)的3D numpy数组大小为(10,518，32)

which has size (10,) to just the 3D numpy array which is of size (10,518, 32)

array([[[0, 0, 0, ..., 0, 0, 0],
        [0, 0, 0, ..., 0, 0, 0],
        [0, 0, 0, ..., 0, 0, 0],
        ..., 
        [0, 0, 0, ..., 0, 0, 0],
        [0, 0, 0, ..., 0, 0, 0],
        [0, 0, 0, ..., 0, 0, 0]]], dtype=uint8)

我尝试将所有内容转换为列表，然后执行np.asarray，还尝试将所有内容定义为相同的dtype = uint8，但我无法将其转换为3D形式.

I've tried converting everything into a list then do np.asarray and also tried defining everything as the same dtype=uint8 but I couldn't get it into the 3D form.

推荐答案

一种方法是分配目标数组并将对象复制为循环.

One way is to allocate the target array and copy the objects in as a loop.

import numpy as np

x = np.array([ np.array([[0, 0, 0, 1, 0, 0],
                         [0, 1, 0, 0, 0, 0],
                         [0, 0, 3, 7, 0, 0],
                         [0, 0, 0, 2, 0, 0]], dtype=np.uint8),
               np.array([[0, 0, 0, 0, 0, 0],
                         [0, 0, 0, 0, 0, 0],
                         [0, 0, 4, 8, 0, 0],
                         [0, 0, 0, 8, 0, 2]], dtype=np.uint8),
               np.array([[0, 0, 0, 0, 0, 0],
                         [1, 0, 0, 0, 0, 0],
                         [0, 0, 5, 9, 0, 0],
                         [0, 0, 0, 1, 0, 0]], dtype=np.uint8)], dtype=object)

print len(x)

print x[0].shape

y=np.zeros([len(x),x[0].shape[0],x[0].shape[1]],dtype=np.uint8)

print y.shape

for i in range(len(x)):
    y[i,:,:] = x[i]

print y

如果我了解您的要求，那么这是理想的结果:

If I understand what you're asking this is the desired result:

3
(4L, 6L)
(3L, 4L, 6L)
[[[0 0 0 1 0 0]
  [0 1 0 0 0 0]
  [0 0 3 7 0 0]
  [0 0 0 2 0 0]]

 [[0 0 0 0 0 0]
  [0 0 0 0 0 0]
  [0 0 4 8 0 0]
  [0 0 0 8 0 2]]

 [[0 0 0 0 0 0]
  [1 0 0 0 0 0]
  [0 0 5 9 0 0]
  [0 0 0 1 0 0]]]

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