如何按值过滤多维数组(具有两个以上级别)? [英] How to filter multi-dimensional array (with more than two levels) by value?
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问题描述
假定给出以下三维数组:
Assuming the following three-dimensional array is given:
Array
(
[0] => Array
(
[0] => Array
(
[foo] => bar
)
[1] => Array
(
[foo] => bar2
)
[2] => Array
(
[foo] => bar3
)
)
[1] => Array
(
[0] => Array
(
[foo] => baz
)
[1] => Array
(
[foo] => bar
)
[2] => Array
(
[foo] => bar5
)
)
)
现在我需要过滤它.如果 [foo]
不等于 bar
,则应删除相应的内部数组.结果将是:
Now I need to filter it. If [foo]
is not equal to bar
the corresponding inner array should get removed. The result would be:
Array
(
[0] => Array
(
[0] => Array
(
[foo] => bar
)
)
[1] => Array
(
[1] => Array
(
[foo] => bar
)
)
)
这可以通过 array_filter
或 array_walk [_recursive]
来实现吗?
Can this be achieved with array_filter
or array_walk[_recursive]
?
推荐答案
可能比所需的更为复杂,但可能是一种组合:
Might be more complex than needed but maybe a combination:
$array = array_map(function($v) {
return array_filter($v, function($v) {
return $v['foo'] === 'bar'; }); }, $array);
这也应该起作用:
foreach($array as &$value) {
$value = array_filter($value, function($v) { return $v['foo'] === 'bar'; });
}
您可以使用递归函数进行更深层或未知的嵌套:
You can use a recursive function for deeper or unknown nesting:
function filterNotSomething(&$array, $key, $val) {
foreach($array as $k => $v) {
if(isset($v[$key]) && $v[$key] !== $val) {
unset($array[$k]);
}
elseif(is_array($v)) {
filterNotSomething($array[$k], $key, $val);
}
if(empty($array[$k])) {
unset($array[$k]);
}
}
}
filterNotSomething($array, 'foo', 'bar');
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