bash中的参数解析 [英] Argument parsing in bash

查看:77
本文介绍了bash中的参数解析的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我是bash的新手.需要针对以下问题的建议.

I am new to bash. Need suggestion for the following problem.

所以我想以这种方式执行脚本

So I want to execute the script in this way

./myscript --bootstrap bootstrap.exe --vmmount ./vmmount --image /dev/sdb2 --target-exe installer.exe [--internal-exe] param1 param2 param3 ...

我已经完成的参数解析器:

Argument parser i have done:

VMMOUNT=""
BOOTSTRAP=""
IMAGE_FILE=""
TARGET_EXE=""
INTERNAL_EXE=""
while : ; do
if [ "$1" = "--vmmount" ] ; then
    [ -n "${VMMOUNT}" ] && usage
    VMMOUNT="$2"
    shift
    shift
elif [ "$1" = "--bootstrap" ] ; then
    [ -n "${BOOTSTRAP}" ] && usage
    BOOTSTRAP="$2"
    shift
    shift
elif [ "$1" = "--image" ] ; then
    [ -n "${IMAGE_FILE}" ] && usage
    IMAGE_FILE="$2"
    shift
    shift       
elif [ "$1" = "--target-exe" ] ; then
    [ -n "${TARGET_EXE}" ] && usage
    TARGET_EXE="$2"
    shift
    shift
elif [ "$1" = "--internal-exe" ] ; then
    [ -n "${INTERNAL_EXE}" ] && usage
    INTERNAL_EXE="true"
    shift
    shift
else
    break
fi
done
my_method "${IMAGE_FILE}" "${VMMOUNT}" "${BOOTSTRAP}" "${TARGET_EXE}" "${INTERNAL_EXE}" 

现在我在解析参数param1和param2等时感到困惑.如何解析它们?我可以使用 $ @ 将参数作为数组或其他任何有效方式吗?

Now I have confusion in parsing the parameters param1 and param2 etc. How to parse them ? Can I use $@ to take the params as array or any other efficient way ?

推荐答案

VMMOUNT=""
BOOTSTRAP=""
IMAGE_FILE=""
TARGET_EXE=""
INTERNAL_EXE=""
while : ; do
  case "$1" in 
    --vmmount)
       [ -n "${VMMOUNT}" ] && usage
       VMMOUNT="$2"
       shift 2 ;;
    --bootstrap)
       [ -n "${BOOTSTRAP}" ] && usage
       BOOTSTRAP="$2"
       shift 2 ;;
    --image)
       [ -n "${IMAGE_FILE}" ] && usage
       IMAGE_FILE="$2"
       shift 2 ;;    
    --target-exe)
       [ -n "${TARGET_EXE}" ] && usage
       TARGET_EXE="$2"
       shift 2 ;;
    --internal-exe)
       [ -n "${INTERNAL_EXE}" ] && usage
       INTERNAL_EXE="true"
       shift ;;
    *)
       break ;;
  esac
done
my_method "${IMAGE_FILE}" "${VMMOUNT}" "${BOOTSTRAP}" "${TARGET_EXE}" "${INTERNAL_EXE}" "$@"

别忘了将 $ @ 用双引号引起来.

Don't forget to enclose $@ in double quotes.

这篇关于bash中的参数解析的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆