如何获得std :: string的尾部? [英] How to get the tail of a std::string?

问题描述

如何获取 std :: string 的尾部?

如果愿望成真，它将像这样工作:

If wishes could come true, it would work like that:

string tailString = sourceString.right(6);

但这似乎太简单了，而且行不通...

But this seems to be too easy, and doesn't work...

有什么好的解决方案吗?

Any nice solution available?

可选问题:如何使用Boost字符串算法库?

Optional question: How to do it with the Boost string algorithm library?

添加:

即使原始字符串小于6个字符，也应保存该方法.

The method should be save even if the original string is smaller than 6 chars.

推荐答案

有一个警告需要注意:if substr 被调用，其位置超出了数组的末尾(优于大小)，然后抛出 out_of_range 异常.

There is one caveat to be aware of: if substr is called with a position past the end of the array (superior to the size), then an out_of_range exception is thrown.

因此:

std::string tail(std::string const& source, size_t const length) {
  if (length >= source.size()) { return source; }
  return source.substr(source.size() - length);
} // tail

您可以将其用作:

std::string t = tail(source, 6);

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