std :: string停在\ 0 [英] std::string stops at \0

问题描述

我在 std :: string ..

问题在于，像在类似C的字符串中一样，'\ 0'被识别为字符串的结尾.

Problem is that '\0' is being recognized as end of the string as in C-like strings.

例如以下代码:

#include <iostream>
#include <string>

int main ()
{
    std::string s ("String!\0 This is a string too!");
    std::cout << s.length(); // same result as with s.size()
    std::cout << std::endl << s;

    return 0;
}

输出以下内容:

7
String!

这是什么问题? std :: string 不应该像对待其他任何字符一样对待'\ 0'吗?

What is the problem here? Shouldn't std::string treat '\0' just as any other character?

推荐答案

考虑一下:如果给您 const char * ，您将如何确定，何为真终止符0，何处为终止符是嵌入一个?

Think about it: if you are given const char*, how will you detemine, where is a true terminating 0, and where is embedded one?

您需要显式传递字符串的大小，或者从两个迭代器(指针?)构造字符串

You need to either explicitely pass a size of string, or construct string from two iterators (pointers?)

#include <string>
#include <iostream>


int main()
{
    auto& str = "String!\0 This is a string too!";
    std::string s(std::begin(str), std::end(str));
    std::cout << s.size() << '\n' << s << '\n';
}

示例: http://coliru.stacked-crooked.com/a/d42211b7199d458d

编辑:@ Rakete1111让我想起了字符串文字:

Edit: @Rakete1111 reminded me about string literals:

using namespace std::literals::string_literals;
auto str = "String!\0 This is a string too!"s;

这篇关于std :: string停在\ 0的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！