检查模板参数是否具有成员函数 [英] Checking whether a template argument has a member function

问题描述

可能重复:
可以写一个要检查函数是否存在的C ++模板?

这与我的早期问题.我想检查模板参数是否包含成员函数.

This is very similar to my earlier question. I want to check whether a template argument contains a member function or not.

我尝试了与上一个问题中接受的答案相似的代码.

I tried this code similar to that in the accepted answer in my previous question.

struct A
{
   int member_func();
};

struct B
{
};

template<typename T>
struct has_member_func
{
   template<typename C> static char func(???); //what should I put in place of '???'
   template<typename C> static int func(...);

   enum{val = sizeof(func<T>(0)) == 1};
};

int main()
{
    std::cout<< has_member_func<B>::val; //should output 0
    std::cout<< has_member_func<A>::val; //should output 1
}

但是我不知道应该使用什么代替 ??? 来使其正常工作.我是SFINAE概念的新手.

But I have no idea what should I put in place of ??? to make it work. I am new to SFINAE concept.

推荐答案

从

Little modification of MSalters' idea from Is it possible to write a C++ template to check for a functions existence? :

template<typename T>
class has_member_func
{
        typedef char no;
        typedef char yes[2];
        template<class C> static yes& test(char (*)[sizeof(&C::member_func)]);
        template<class C> static no& test(...);
public:
        enum{value = sizeof(test<T>(0)) == sizeof(yes&)};
};

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