C ++ 11：启动具有成员函数的线程，并将其作为参数 [英] C++ 11 : Start thread with member function and this as parameter

问题描述

使用此代码，我得到了错误：

Using this code, I got and error :

错误1错误C2064：term不评估为一个函数带1个参数c：\program files ）\microsoft visual studio 11.0 \vc\include\functional 1152 1管道

Error 1 error C2064: term does not evaluate to a function taking 1 arguments c:\program files (x86)\microsoft visual studio 11.0\vc\include\functional 1152 1 Pipeline

class PipelineJob {
private:
    std::thread *thread;
    void execute(PipelineJob* object);
public:

    void execute(PipelineJob* object)
    {
    }

    PipelineJob()
    {
        this->thread = new std::thread(&PipelineJob::execute, this);
    }
};

我尝试了很多变化，现在如何解决这个问题？

I tried many variation, any one now how to solve this?

推荐答案

为了简单起见，删除模板和指针，这或多或少是你想要的：

Removing the templates and the pointers for simplicity, this is more or less what you would want:

class PipelineJob 
{
private:
    std::thread thread_;
    void execute(PipelineJob* object) { ..... }
public:
    PipelineJob()
    {
      thread_ = std::thread(&PipelineJob::execute, this, this);
    }
    ~PipelineJob() { thread_.join(); }
};

请注意， this std :: thread 构造函数：一次为成员函数的隐式第一个参数，第二个为可见参数 PipelineJob * object

Note that this is passed two times to the std::thread constructor: once for the member function's implicit first parameter, the second for the visible parameter PipelineJob* object of the member function.

如果您的执行成员函数不需要外部 PipelineJob 指针，那么你将需要像

If your execute member function does not need an external PipelineJob pointer, then you would need something like

class PipelineJob 
{
private:
    std::thread thread_;
    void execute() { ..... }
public:
    PipelineJob()
    {
      thread_ = std::thread(&PipelineJob::execute, this);
    }
    ~PipelineJob() { thread_.join(); }
};

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