我该如何编码和传递(对std :: vector的引用)? [英] How do I code and pass a (reference to a std::vector)?
问题描述
我似乎无法正确理解.
class Tree
{
Node* root;
vector& dict;
}
class Node
{
vector& dict;
char* cargo;
Node left;
Node right;
}
我希望Tree的每个实例都有自己的字典,并希望将对字典的引用传递给节点构造函数,该构造函数将递归地将引用传递给每个子节点,以便每个Node可以输入一个指向本身在字典中.
I want each instance of Tree to have it's own dict, and I want it to pass a reference to the dict to the node constructor, which would recursively pass the reference to each child node so that each Node can enter a pointer to itself in the dict.
我在语法上遇到很多麻烦:
I'm having a lot of trouble with the syntax to:
- 初始化向量
- 将对向量的引用传递给Node构造函数
- 在Node构造函数中接收引用
我知道这些东西很基础.我在自学c ++.
I know this stuff is pretty basic. I'm teaching myself c++.
谢谢
推荐答案
您还没有指定尝试的方法,但没有用,但是我怀疑您在构造函数中遇到了麻烦,因为引用不能分配给;您必须对其进行初始化.
You haven't specified what you've tried that isn't working, but I suspect you are having trouble in the constructors because a reference can't be assigned to; you have to initialize it.
此外,当您使用 std :: vector
时,必须使用模板参数作为元素类型.因此,您不能只使用 vector&
,还需要 vector< Something>&
,其中 Something
是元素类型是什么.
Also, when you use std::vector
, you have to use a template parameter for the element type. So you can't just use vector&
, you need vector<Something>&
, where Something
is whatever the element type is.
所以,您可能想要这样的东西:
So, you probably want something like this:
class Tree
{
private:
Node* root;
std::vector<Something>& dict;
public:
Tree(Node* aRoot, std::vector<Something>& aDict): root(aRoot), dict(aDict) {}
};
class Node
{
private:
std::vector<Something>& dict;
char*cargo;
Node left;
Node right;
Node(std::vector<Something>& aDict, char* aCargo): dict(aDict), cargo(aCargo) {}
};
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