转发声明和shared_ptr [英] Forward declarations and shared_ptr

问题描述

我正在尝试重构代码，以便使用前向声明而不是包含许多标头.我对此并不陌生，并且对boost :: shared_ptr有疑问.

I'm trying to refactor my code so that I use forward declarations instead of including lots of headers. I'm new to this and have a question regarding boost::shared_ptr.

说我有以下界面:

#ifndef I_STARTER_H_
#define I_STARTER_H_

#include <boost/shared_ptr.hpp>

class IStarter
{
public:
    virtual ~IStarter() {};

    virtual operator()() = 0;
};

typedef boost::shared_ptr<IStarter> IStarterPtr;

#endif

然后我在另一个类中有一个函数，该函数将IStarterPtr对象作为参数，例如:

I then have a function in another class which takes an IStarterPtr object as argument, say:

virtual void addStarter(IStarterPtr starter)
{
    _starter = starter;
}
...
IStarterPtr _starter;

如何在不包含IStarter.h的情况下转发IStarterPtr声明?

how do I forward declare IStarterPtr without including IStarter.h?

如果相关，我正在使用C ++ 98.

I'm using C++98 if that is of relevance.

推荐答案

只要不对它们调用*或->，共享指针就可以与正向声明的类型一起使用，因此应该可以简单地编写:-

Shared pointers work with forward declared types as long as you dont call * or -> on them so it should work to simply write :-

class IStarter;
typedef boost::shared_ptr<IStarter> IStarterPtr;

您当然需要包含< boost/shared_ptr.hpp>

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