代码块中的-fpermissive选项.我在哪里放置"-fpermissive"?选项? [英] -fpermissive option in codeblocks. Where do I put that "-fpermissive" option?

问题描述

#include <iostream>
#include <fstream>
#include <stdio.h>
#include <math.h>

我需要有关此代码的帮助.我的编译器一直要求我使用-fpermissive选项，但我不知道在哪里输入它.我已经粘贴了下面的代码和显示的错误.

I need help with this code. My compiler keeps asking me to use the -fpermissive option but I don't know where to input it. I've pasted the code below and the error that is shown.

using namespace std;

int cx = 0, cy = 0;

double x =0, y=0,  r = 5;


int main(){

ofstream myfile;

myfile.open("dingo.txt");

for(int g =0 ; g <= 360; g++)

//find x and y

//Get points of a circle.

x = cx + r * cos(g);

y = cy + r * sin(g);

//This is what pops up below:

//In function int main()':

//Error: name lookup of 'g' changed for ISO 'for' scoping [-fpermissive]

//note: (if you use '-fpermissive' G++ will accept your code)

//where should I enter the required option?

myfile << "X: " << x << "; Y: " << y <<endl;

myfile.close();

return 0;

}

推荐答案

您可以在设置" > 中的其他选项" 下添加更多编译器标志.编译器"

You can add more compiler flags under "Other Options" in "Settings" > "Compiler"

尽管我认为您应该先修复代码.例如， std :: sin 和 std :: cos 接受弧度，而不接受度数.您还需要在 for 语句周围加括号.

Although I think you should fix your code first. For example, std::sin and std::cos accepts radians, not degrees. You also need braces around your for statement.

for(int g =0 ; g <= 360; g++) {
    //code here.
}

这篇关于代码块中的-fpermissive选项.我在哪里放置"-fpermissive"?选项?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！