设置matplotlib彩条范围(范围大于绘制的值) [英] Setting matplotlib colorbar range (larger range than the values plotted)
问题描述
我想绘制一些数据(0到18之间),但我希望颜色条显示0到40之间的范围.在浏览了几个在线示例之后,我对如何实现所需的目标一无所知!
I want to plot some data (between 0 and 18) but I want the colorbar to show a range between 0 and 40. After going through several online examples, I have no idea on how to achieve what I need!
这是一个简单的例子:
import matplotlib.pyplot as plt
import numpy as np
rd = np.random.rand(40,100) # random samples from a uniform distribution over [0, 1]
surface = 18 * rd # maximum value will be 18
fig = plt.figure()
ax = fig.add_subplot(111)
cores = ax.contourf(surface[:], vmin=0, vmax=40)
cbar = plt.colorbar(cores)
我也尝试过:
cbar = plt.colorbar(cores, extend='both', extendrect=True)
cbar.set_clim(0, 40.)
但是我不断获得相同的图像,其色标范围为0到20!我知道我可以使用 set_over
方法,但是我不想获得单一颜色...我想要我的整个颜色范围(如 cores
中所定义)0至40)出现!
But I keep getting the same image, with a colorbar ranging from 0 to 20!
I know I could use the set_over
method, but I don't want to get a single color... I want my whole color range (as defined in cores
, from 0 to 40) to appear!
感谢您的帮助!
推荐答案
我终于设法解决了它.我必须传递一个关键字来控制绘制级别,而不是 vmin
和 vmax
,
I finally managed to solve it.
Instead of vmin
and vmax
, I must pass a keyword to control the levels to draw, like this:
import matplotlib.pyplot as plt
import numpy as np
rd = np.random.rand(40,100)
surface = 18 * rd # maximum value will be 18
fig = plt.figure()
ax = fig.add_subplot(111)
cores = ax.contourf(surface[:], levels=range(41))
cbar = plt.colorbar(cores)
plt.show()
然后我得到了想要的图像:
And I get the image I wanted:
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