GetAsyncKeyState和使用JNA VirtualKeys /特殊字符(JAVA) [英] GetAsyncKeyState and VirtualKeys/special characters using JNA (JAVA)

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问题描述

我工作的一个双向私聊,将在全屏幕游戏的工作。

I am working on a two-way private chat that will work in a full screen game.

这是必需的,让用户在屏幕上的,即使它不具有焦点

This is required to let the user to type into a semi-transparent textbox at the top of the screen even when it doesn't have focus.

使用以下code,我可以检测所有物理按键,但有一个艰难的时间与虚拟按键。

Using the following code, I can detect ALL physical keys, but have a tough time with virtual keys.

SHIFT 进行检测。

2 进行检测。

SHIFT + 2 同时检测作为单独的按键(即使 [SHIFT + 2] 给<$ ç我的键盘上的$ C> @ )。即:程序输出两个移位,和2,但不是他们生产什么: @

However Shift + 2 are detected both as separate keys (Even though [SHIFT+2] gives @ on my keyboard). IE: The program outputs both SHIFT, and 2, but not what they produce: @.

问题是,我将如何转换为根据在键盘上的字符?
例如:

The problem is, how will I convert to a character depending on the keyboard? For example:


  • 在英国键盘,SHIFT + 2会给我(引号)。

  • 在美国键盘,SHIFT +2会给我 @

  • On a UK Keyboard, SHIFT+2 will give me " (quotes).
  • On a US keyboard, SHIFT +2 will give me @.

如何转换为特定的字符取决于键盘上?

How can I convert to a specific character depending on the keyboard?

下面是code迄今:

static interface User32 extends Library {
    public static User32 INSTANCE = (User32) Native.loadLibrary("User32", User32.class);

    short GetAsyncKeyState(int key);
    short GetKeyState(int key);

    IntByReference GetKeyboardLayout(int dwLayout);
    int MapVirtualKeyExW (int uCode, int nMapType, IntByReference dwhkl);

    boolean GetKeyboardState(byte[] lpKeyState);

    int ToUnicodeEx(int wVirtKey, int wScanCode, byte[] lpKeyState, char[] pwszBuff, int cchBuff, int wFlags, IntByReference dwhkl);

}



public static void main(String[] args)  {   
    long currTime = System.currentTimeMillis();

    while (System.currentTimeMillis() < currTime + 20000)
    {
        for (int key = 1; key < 256; key++)
            {
                if (isKeyPressed(key)) 
                    getKeyType(key);
            }
    }
}



private static boolean isKeyPressed(int key)
{
    return User32.INSTANCE.GetAsyncKeyState(key) == -32767;
}



private static void getKeyType(int key)
{

    boolean isDownShift = (User32.INSTANCE.GetKeyState(VK_SHIFT) & 0x80) == 0x80;
    boolean isDownCapsLock = (User32.INSTANCE.GetKeyState(VK_CAPS)) != 0;


    byte[] keystate = new byte[256];
    User32.INSTANCE.GetKeyboardState(keystate); 


    IntByReference keyblayoutID = User32.INSTANCE.GetKeyboardLayout(0);
    int ScanCode  = User32.INSTANCE.MapVirtualKeyExW(key, MAPVK_VK_TO_VSC, keyblayoutID);






    char[] buff = new char[10];

    int bufflen = buff.length;
    int ret = User32.INSTANCE.ToUnicodeEx(key, ScanCode, keystate, buff, bufflen, 0, keyblayoutID);


    switch (ret)
    {
        case -1: 
            System.out.println("Error");
        break;

        case 0:  // no translation

        break;

        default: 
        System.out.println("output=" + String.valueOf(buff).substring(0, ret));
    }




}

它工作正常,并输出键pressed,但不使用Shift +组合工作。我知道我可以做一个开关,改变SHIFT + 3£,但这不会与不同的键盘工作。

It works fine and outputs the keys pressed, but doesn't work with Shift + combinations. I realize that I could do a "Switch" and change Shift+3 to "£", but this will not work with different keyboards.

推荐答案

我知道了。许多,许多,许多小时的搜索后,我设法创建一个组合转换为应该对当前的键盘布局什么样的方法。它不处理死键(如重音),但它捕获所有的 [SHIFT +组合] ,我需要它来赶上。

I got it. After many, many, many hours of searching, I managed to create a method that converts the combination to what it should be on the current keyboard layout. It doesn't deal with dead-keys (such as accents), but it catches all the [SHIFT+Combinations] that I need it to catch.

要使用它,如下所示调用它:

To use it, call it as follows:

getCharacter(int vkCode, boolean shiftKeyPressed);

所以,看这个魔术。如果我要得到什么 SHIFT + 3 会给我我的键盘(£),我使用的:

So, watch this magic. If I want to get what SHIFT+3 will give me on my keyboard (£), I use:

getCharacter(KeyEvent.VK_3, true);

下面是code:

public static char getCharacter(int vkCode, boolean shiftKeyPressed)
{

    byte[] keyStates = new byte[256]; //Create a keyboard map of 256 keys

    if (shiftKeyPressed)
    {
        keyStates[16]=-127; //Emulate the shift key being held down
        keyStates[160]=-128; //This needs to be set as well
    }

    IntByReference keyblayoutID = User32.INSTANCE.GetKeyboardLayout(0); //Load local keyboard layout

    int ScanCode  = User32.INSTANCE.MapVirtualKeyExW(vkCode, MAPVK_VK_TO_VSC, keyblayoutID); //Get the scancode

    char[] buff = new char[1];

    int ret = User32.INSTANCE.ToUnicodeEx(vkCode, ScanCode, keyStates, buff, 1, 0, _currentInputLocaleIdentifier);

    switch (ret)
    {
    case -1: //Error
        return (char) -1;

    case 0:  //No Translation
        return (char) 0;

    default: //Returning key...
        return buff[0];
    }
}

下面是声明:

final static int MAPVK_VK_TO_VSC = 0;
static IntByReference _currentInputLocaleIdentifier; 

static interface User32 extends Library {

    public static User32 INSTANCE = (User32) Native.loadLibrary("User32", User32.class);


    IntByReference GetKeyboardLayout(int dwLayout);
    int MapVirtualKeyExW (int uCode, int nMapType, IntByReference dwhkl);

    boolean GetKeyboardState(byte[] lpKeyState);

    int ToUnicodeEx(int wVirtKey, int wScanCode, byte[] lpKeyState, char[] pwszBuff, int cchBuff, int wFlags, IntByReference dwhkl);

}

非常感谢你BrendanMcK,谁帮我去这个解决方案。

A big thank you to BrendanMcK, who helped me to get to this solution.

这篇关于GetAsyncKeyState和使用JNA VirtualKeys /特殊字符(JAVA)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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