数组运算符[]重载const和非const版本 [英] Array operator [] overloading const and non-const versions

问题描述

我得到了一个实现模板数组类的任务.要求之一是重载[]运算符.我制作了这两个const和非const版本，它们似乎运行良好.

I got an assignment to implement a template array class. One of the requirement is to overload the [] operator. I made this two const and non-const version which seems to be working fine.

const T& operator[](const unsigned int index)const

和

T& operator[](const unsigned int index)

我的问题是编译器将如何知道要运行哪一个当我做类似的事情时:

My question is how will the compiler know which one to run when i will do something like:

int i=arr[1]

在非常量数组上吗?

推荐答案

总是在非const数组上调用非const函数，而在const数组上调用const函数.

The non-const function will always be called on a non-const array, and the const function on a const array.

当两个具有相同名称的方法时，编译器会根据参数的类型和隐式对象参数(arr)的类型来选择最适合的一个.

When you have two methods with the same name, the compiler selects the best-fitting one based on the type of the arguments, and the type of the implicit object parameter (arr).

前几天我刚刚回答了一个类似的问题，您可能会发现有帮助: https://stackoverflow.com/a/16922652/2387403

I just answered a similar question the other day, you may find it helpful: https://stackoverflow.com/a/16922652/2387403

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