删除"x天从datetime.timedelta对象开始 [英] Removing " x days " from datetime.timedelta object

问题描述

我需要创建一个报告，在其中我需要减去两个日期并以的形式返回％H:％M％S

I need to create a report where I need to subtract two dates and return it in the form of %H:%M%S

这是我插入到列表中的减法:

This is the subtraction which I inserted into a list :

time_difference_temp=datetime.strptime(next_time,"%Y-%m-%d %H:%M:%S") - datetime.strptime(current_time,"%Y-%m-%d %H:%M:%S")
time_difference.append(time_difference_temp)
return time_difference

此列表返回到>

this list returns to >

def push_to_csv(time_difference):
    df = pd.read_csv('time_differences.csv')
    df["Delta"] = time_difference
    df.dropna(subset=["Data"], inplace=True)
    df.to_csv("Final_ReportX.csv")

在csv Final_ReportX中，它以以下格式保存:0天00:05:39

in the csv Final_ReportX it saved in the form : 0 days 00:05:39

我需要它仅返回00:05:39，没有几天.

*正则表达式不是一个选择

*regex is not an option

谢谢！

推荐答案

您可以使用将timedelta转换为H:M:S字符串的自定义函数:

you can use a custom function that converts timedelta to H:M:S string:

def td_to_str(td):
    """
    convert a timedelta object td to a string in HH:MM:SS format.
    """
    hours, remainder = divmod(td.total_seconds(), 3600)
    minutes, seconds = divmod(remainder, 60)
    return f'{int(hours):02}:{int(minutes):02}:{int(seconds):02}'

s = pd.Series(pd.to_timedelta(['1 day, 00:05:39']))

s.apply(td_to_str)
# 0    24:05:39
# dtype: object

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