TypeError：无法比较datetime.timedelta到float [英] TypeError: can't compare datetime.timedelta to float

问题描述

我正在使用python脚本来计算开始日期和结束日期格式之间的持续时间，例如 20140520160000 和 20140520170000 ，这样我就可以开始工作了。

I'm working on my python script to work out the duration times between start date and end date format like 20140520160000 and 20140520170000 so I can get the hour.

我在使用此代码时遇到了麻烦：

I'm having a trouble with this code:

if epgDuration >= 0.10 and epgDuration <= 0.30:
   epgwidth = "250"

当我尝试比较0.10分钟和0.30分钟之间的时间范围时，我得到一个错误。

I get an error when I'm trying to compare the range of the times between 0.10 mins and 0.30 mins.

我得到的错误是：TypeError：无法比较datetime.timedelta浮动。

The error I get is: TypeError: can't compare datetime.timedelta to float.

错误在此行上跳跃：

if epgDuration >= 0.10 and epgDuration <= 0.30:

结果如下：

14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 2:30:00
14:44:55 T:1580  NOTICE: 3:00:00
14:44:55 T:1580  NOTICE: 1:00:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 1:00:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 0:30:00
14:44:55 T:1580  NOTICE: 0:30:00

以下是我用来设定时间的代码：

Here is the code when I use to duration the times:

for row in programs:
    program_startdate = str(row[2])
    program_endDate = str(row[3])

    try:
       start_date = datetime.datetime.strptime(program_startdate, "%Y%m%d%H%M%S")
       end_date = datetime.datetime.strptime(program_endDate, "%Y%m%d%H%M%S")
    except TypeError:
       start_date = datetime.datetime.fromtimestamp(time.mktime(time.strptime(program_startdate, "%Y%m%d%H%M%S")))
       end_date = datetime.datetime.fromtimestamp(time.mktime(time.strptime(program_endDate, "%Y%m%d%H%M%S")))

    #workout the duration times to get the program time
    epgDuration = end_date - start_date

    if epgDuration >= 0.10 and epgDuration <= 0.30:
       epgwidth = "250"

    elif epgDuration >= 1.00 and epgDuration <= 1.29:
         epgwidth = "500"
    print epgwidth

推荐答案

实际上，您不能将 timedelta 与浮点值进行比较。

Indeed, you cannot compare a timedelta to a float value.

您可以将对象转换为秒：

if 600 <= epgDuration.total_seconds() <= 1800:

其中10分钟是600秒，而30分钟是1800。

where 10 minutes is 600 seconds, and 30 minutes is 1800.

或创建新的 timedelta（）对象与以下对象进行比较：

Or create new timedelta() objects to compare against:

epgwidth = "0"

if timedelta(minutes=10) <= epgDuration <= timedelta(minutes=30):
    epgwidth = "250"

elif timedelta(hours=1) <= epgDuration <= timedelta(hours=1.5):
    epgwidth = "500"

我给了 epgwidth 在 if 语句之前的默认值，以防时差不落在10-30分钟或1- 1.5小时范围。

I've given epgwidth a default value before the if statements for the case where the time difference is not falling in the 10-30 minutes or 1-1.5 hour ranges.

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