TypeError:必须为str，而不是datetime.timedelta [英] TypeError: must be str, not datetime.timedelta

问题描述

这是我的代码，它对于第一次打印可以正常工作，并给我这个错误TypeError:必须为str，而不是datetime.timedelta

here is my code it works fine for the first print and the give me this error TypeError: must be str, not datetime.timedelta

import datetime
hour = datetime.datetime.now().hour
tomorrow = datetime.datetime.now()
for i in range(50):
    hour += 1
    print(hour)
    if hour >= 23:
        tomorrow = tomorrow + datetime.timedelta(days=1)
        tomorrow = tomorrow.strftime('%d/%m/%Y')
        hour = 9
        print (tomorrow)

这是输出:

13
14
15
16
17
18
19
20
21
22
23
07/12/2017
10
11
12
13
14
15
16
17
18
19
20
21
22
23
Traceback (most recent call last):
  File "C:\Users\hamza.salhi\Desktop\datetime test.py", line 8, in <module>
    tomorrow = tomorrow + datetime.timedelta(days=1)
TypeError: must be str, not datetime.timedelta

请有人告诉我为什么它先可以正常工作，然后我得到那个错误

please can someone tell me why it works fine at first then i get that error

推荐答案

它第一次起作用是因为明天是 datetime.datetime 实例，然后:

It works the first time because tomorrow is a datetime.datetime instance then:

tomorrow = datetime.datetime.now()

但是，第一次之后，您将明天替换为字符串:

However, after that first time, you replace tomorrow with a string:

tomorrow = tomorrow.strftime('%d/%m/%Y')

您不能在字符串中添加 timedelta()对象.不要重新绑定明天.要么将字符串分配给其他名称，要么仅格式化对象以进行打印(而根本不将其分配给名称):

You can't add a timedelta() object to a string. Don't rebind tomorrow. Either assign the string to a different name, or only format the object for printing (and not assign it to a name at all):

if hour >= 23:
    tomorrow = tomorrow + datetime.timedelta(days=1)
    tomorrow_formatted = tomorrow.strftime('%d/%m/%Y')
    hour = 9
    print(tomorrow_formatted)  # different name
    print(tomorrow.strftime('%d/%m/%Y'))  # print the `strftime()` result

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