如何在python中修复'ValueError:Math domain error'? [英] How to fix 'ValueError: math domain error' in python?

问题描述

我正在尝试编写一个计算公式y =√x* x + 3 * x-500的程序，间隔为[x1; x2]，且f1 = 15，x2 = 25.

I am trying to write a program which calculates formula y=√x*x + 3*x - 500, Interval is [x1;x2] and f.e x1=15, x2=25.

我尝试使用异常处理，但没有帮助.现在我尝试使用的代码给了我:ValueError:数学域错误

I tried to use Exception Handling but it didn't help. And the code I try to use now gives me: ValueError: math domain error

import math

x1 = int(input("Enter first number:"))
x2 = int(input("Enter second number:"))
print(" x", "   y")
for x in range(x1, x2):
    formula = math.sqrt(x * x + 3 * x - 500)
    if formula < 0:
        print("square root cant be negative")
    print(x, round(formula, 2))

输出应如下所示:

x   y
15 ***
16 ***
17 ***
18 ***
19 ***
20 ***
21 2.00
22 7.07
23 9.90
24 12.17
25 14.14

推荐答案

平方根的参数不能为负.在这里使用异常处理完全可以，请参见下文:

The argument of square root mustn't be negative. It's perfectly fine to use exception handling here, see below:

游乐场: https://ideone.com/vMcewP

import math


x1 = int(input("Enter first number:\n"))
x2 = int(input("Enter second number:\n"))

print(" x\ty")
for x in range(x1, x2 + 1):
    try:
        formula = math.sqrt(x**2 + 3*x - 500)
        print("%d\t%.2f" % (x, formula))
    except ValueError:  # Square root of a negative number.
        print("%d\txxx" % x)

---

资源:

• wiki.python.org:处理异常

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