在C ++中按完整路径打开文件 [英] Open file by its full path in C++

问题描述

我希望用户提供文件存在的完整路径，而不仅仅是文件名.如何以这种方式打开文件?

I want the user to give me the full path where the file exists and not just the file name. How do I open the file this way?

是这样的吗?

ifstream file;
file.open("C:/Demo.txt", ios::in);

这似乎不起作用.

推荐答案

在Windows中，通常使用反斜杠字符作为路径分隔符.所以:

Normally one uses the backslash character as the path separator in Windows. So:

ifstream file;
file.open("C:\\Demo.txt", ios::in);

请记住，以C ++源代码编写时，必须使用双反斜杠，因为反斜杠字符本身在双引号引起来的字符串中表示特殊的含义.因此，上面提到的是文件 C:\ Demo.txt .

Keep in mind that when written in C++ source code, you must use the double backslash because the backslash character itself means something special inside double quoted strings. So the above refers to the file C:\Demo.txt.

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