对于gtest，如何模拟名称相同但类型不同的方法 [英] For gtest, how to mock methods which have the same name, but different types

问题描述

我使用Gtest验证我的C ++代码，现在我遇到了模拟问题.由于多种原因，我有一些方法，它们的名称相同，但是类型参数和实现不同，例如

I use Gtest to verify my C++ code, and now I face a mocking problem. For several reasons, I have some methods, which have the same name, but different type arguments and implementation, like

void foo(int& i);
void foo(double& d);
void foo(float& f);

对他们来说，我制作了模拟方法，例如

For them, I make mock methods, like

MOCK_METHOD1(foo, void(int&));
MOCK_METHOD1(foo, void(double&));
MOCK_METHOD1(foo, void(float&));

但是，我无法为他们使用EXPECT_CALL.在测试代​​码中，我为foo(int)设置了操作，例如

However, I could not use EXPECT_CALL for them. In a test code, I set action for foo(int), like

EXPECT_CALL(mock_object, foo(_)).WillOnce(DoAll(SetArgReferee<0>(10),Return()));

但是，编译器失败，因为int，double和float之间的目标不明确.

but, compiler failed because target is ambiguous among int, double and float.

是否可以将EXPECT_CALL用于特定类型的模拟方法?

Is there any way to use EXPECT_CALL for specific type mock method?

我无法使用testing :: MatcherCast和testing :: SafeMatcherCast，因为它们仅接受const类型.但是，我需要更新参数，因此无法使用const.

I failed to use testing::MatcherCast and testing::SafeMatcherCast, because they only accept const type. However, I need to update the argument, so I could not use const.

推荐答案

您可以使用键入的通配符(

You can use typed wildcard (documentation):

EXPECT_CALL(mock_object, foo(An<int&>())).WillOnce(SetArgReferee<0>(10));
EXPECT_CALL(mock_object, foo(A<double&>())).WillOnce(SetArgReferee<0>(10.));

A<> 和 An<> 的含义完全相同，它们有两个名称，目的是为了更好地阅读.在 godbolt

A<> and An<> mean exactly the same, they have two names just for nicer reading. See it online on godbolt

旁注:您不必通过 void 方法进行 Return().

Side note: You don't have to Return() from void method.

这篇关于对于gtest，如何模拟名称相同但类型不同的方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！