如何在不使用字符串的情况下确定输入的整数是否包含某些数字 [英] How to determine if an inputted integer contains certain digits without using strings

问题描述

在此程序中，我应该确定用户输入的整数是否包含某个数字(在本例中为7和3)，然后返回一个布尔值.到目前为止，我有:

In this program I am supposed to figure out if the integer that the user enters contains a certain digit (in this case 7 and 3), and then return a boolean. So far I have:

public static boolean contains(int num, int x) {
    Scanner input = new Scanner(System.in);
    int currentLength = numberDigits(num); //method that counts the number of digits in the inputed integer

    int digit;   // current first digit

    int firstNumber = firstNum(num);
    boolean digitTrue = false;   

    while (currentLength > 0 ) {
        digit = firstNumber;
        if (num == x)
        {
            digitTrue= true;
        } else {
            digitTrue= false;
        }
    }
    return digitTrue;
}

推荐答案

解决这个问题的最好方法是使用％.％或Modulus返回一个数字的余数/一个数字的余数.例如5％2 = 1或355％10 =5.如果您只想检查一个大数字是否为一位数字，我建议使用此方法

The best way to solve this that I know of is to use %. % or Modulus returns the remainder of one number / by another number. For example 5 % 2 = 1 or 355 % 10 = 5. If you are looking only to check a large number for single digit numbers I would suggest this method

public static boolean contains(int num, int x){

while(num >= 0){
    if (num % 10 == x){
        return true;
    }
    if (num > 0){
        num = num / 10;
    }else{
        return false;
    }
}
return false;
}

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